. The Decorator's assistant. h, and then the exposedpart is to be coated with iron as above des-cribed ; the varnish must then be removed andthe metal immersed in the cyanide of potas-sieum solution, till the design is of a sufficientdepth. Wales a Wonder of the World.—Thereis not one solitary line of telegraph throughoutthe whole principality of Wales! 190 THE DECORATOR S ASSISTANT. M^nrnxaiion of ^upttUus. (Contintied from page 182.) PROBLEM XIII. The area of a circle being given, to find thediameter. Divide the area of the circle by .7854, andtake the square root of the quotient, which will
. The Decorator's assistant. h, and then the exposedpart is to be coated with iron as above des-cribed ; the varnish must then be removed andthe metal immersed in the cyanide of potas-sieum solution, till the design is of a sufficientdepth. Wales a Wonder of the World.—Thereis not one solitary line of telegraph throughoutthe whole principality of Wales! 190 THE DECORATOR S ASSISTANT. M^nrnxaiion of ^upttUus. (Contintied from page 182.) PROBLEM XIII. The area of a circle being given, to find thediameter. Divide the area of the circle by .7854, andtake the square root of the quotient, which willbe the diameter. Example.—What is the diameter of a circle,the area being square feet? .7854) ( 1963515708 3927039270 225 (15 = [required. 25) 125125 PROBLEM XIV. To find the area of a sector. Multiply the radius by the arc, and half theproduct will be the area. Example.—What will be the area of thesector A B c A, its radius b c being 30 inches,and the length of the arc a b inches 2. 2) 549 = area required. PROBLEM XV, To find the area of the segment of a circle. Find the area of the sector a d c b a, or thatof A D c E F A, by the preceding problem, ac-cording as the area of the less or greater seg-ment is required. Find the area of the triangle a c d, formedby the chord a c of the segments, and the radiiD a, D c, of the sectors. Then, the sum or difference of these areas,according as the segment is greater or lessthan a semicircle, will be the area.
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