. The elements of railroad engineering . - 24 + 30 = 234 pounds to the scale to which theweights were laid off. It will be noticed in the above thatthe equal subdivisions of the load were laid off on O C untilthat one was reached on which the concentrated loads rested,and that the concentrated loads were laid off before theequal subdivision on which the concentrated load rested waslaid off. Had one of the concentrated loads been to theright of the center of gravity of the subdivision on which it 4SR STRENGTH OF MATERIALS. rests^ the weight of the subdivision would have been laid offfirst. Loca


. The elements of railroad engineering . - 24 + 30 = 234 pounds to the scale to which theweights were laid off. It will be noticed in the above thatthe equal subdivisions of the load were laid off on O C untilthat one was reached on which the concentrated loads rested,and that the concentrated loads were laid off before theequal subdivision on which the concentrated load rested waslaid off. Had one of the concentrated loads been to theright of the center of gravity of the subdivision on which it 4SR STRENGTH OF MATERIALS. rests^ the weight of the subdivision would have been laid offfirst. Locate the centers of gravity of the equal subdivisionsand draw the verticals through them as in the previous a pole P, draw the rays, the diagram of bendingmoments, and the shear zyivs, M q, as previously ^1. ,-^ Fig. J26. ^iV To find the maximum bending moment, the shear linemust be drawn and its intersection with the shear axisdetermined. The weight of the uniform load per foot of length isJLSjO = 12 lb. The weight of that part between A and thecenter of the 24:-lb. weight is 12 X 5 = GO lb. Lay off(9 i = GO lb. and draw 1-2 horizontal, cutting the verticalthrough the center of the 24-lb. wtight in 2. Draw O 2 andit will be a part of the shear line. Lay off 2-S verticallydownwards, equal to 24 lb., locating the point 5. LayoffO Jf equal to 12 X 11 + 24 = loG lb., and draw the , cutting the vertical through the center of the 30-lb. STRENGTH OF MATERIALS. 489 weight in 5. Join 3 and 5 by the straight line 3-5. Lay off5-6 vertically downwards equal to 30 lb. Draw the horizon-tal C N, intersecting the vertical B q N N and join 6 andN by the straight line 6 N. The broken line O 2-3-5-6 N isthe shear line and cuts the shear axis in the point r. Draw-ing the vertical r b &l


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Keywords: ., bookcentury1800, bookdecade1890, booksubjectrailroadengineering