Locomotive boiler construction; a practical treatise for boilermakers, boiler users and inspectors .. . derstood byseveral examples,(i) 173X317131 Log (T73I^I3I7)-=Log 173 + Log 317 — Log 131 Now hunt up 17 in the first column and 3 in the topcolumn, the intersection gives The constant 2is always one less than the number of figures. We then have Log 173 = Log 317 = Minus Log of 13 4739091 = The number corresponding to>und thus, from the table: this logarithm is 62221 =62118 = = Log 419= Log 418 = difference 103 = 6218262118 64 103 10 —- 6 The
Locomotive boiler construction; a practical treatise for boilermakers, boiler users and inspectors .. . derstood byseveral examples,(i) 173X317131 Log (T73I^I3I7)-=Log 173 + Log 317 — Log 131 Now hunt up 17 in the first column and 3 in the topcolumn, the intersection gives The constant 2is always one less than the number of figures. We then have Log 173 = Log 317 = Minus Log of 13 4739091 = The number corresponding to>und thus, from the table: this logarithm is 62221 =62118 = = Log 419= Log 418 = difference 103 = 6218262118 64 103 10 —- 6 Therefore the number corresponding to = 41&.6 342 General tables. Another useful table is table three. If we have anangle of say 40 degrees, , and wish to know theside T, then A is 65 inches. Refer to table three andfind the tangent of 40 degrees, equal to .8391, and thismultiplied by 65 gives for the length of T. Ifon the other hand we knew what T was, from this tablewe could obtain what the angle opposite to T must be. In a similar way, from table four, w; can find the. Figure 332Showing angles. co-tangent and from the table we could obtain the sineand cosine of different angles. In finding the weight of water in boilers, we knowthe distance from the water level or the top gage cock,to the top line of the boiler. See H, Fig. 333. We alsoknow the inside diameter of the boiler D and the lengthL for the different sheets. In obtaining the area of thesegment H, we use table five. 343 General of segment = D2 X M M~*=-^ = .2o6 D 68 The value for M corresponding to .206 is found tobe .116651 by reference to table five. Therefore segment area = D2 X .1116651 = 682 116651 = 541 The volume of the water in the boiler in gallonswould be (68 area — Segment area) X L 231(3632 — 541) XL 3091 X 116 231 231 = 1553 gallons. In a similar manner each one of the other courses can becalculated.
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Keywords: ., bookcentury1900, bookdecade1910, bookidlocomotivebo, bookyear1912
